#51: Broken shell command substitution in crontab

Solved!
on June 04, 2009, 11:05 AM UTC   —   from   92049143cabb7ba896d7c06e19906303_small yliu    ( 2,035 views )
In a cronjob, I want to execute a date sub-command and substitute the results in place into the overall shell command. Something like: 1 5 * * * bash -c 'cp /foo/bar /foo/bar.$(date +%Y%m%d).sql' Unfortunately, this breaks with an error at runtime: /bin...
Tags: shell scripting, crontab, Linux, cronjob, cron, bash, shell, UNIX
1 solution | 2 references     Add Solution | Add Reference